Question:

Young’s modulus of elasticity π‘Œ is expressed in terms of three derived quantities, namely, the gravitational constant 𝐺, Planck’s constant β„Ž and the speed of light 𝑐, as π‘Œ = π‘π›Όβ„Žπ›½πΊπ›Ύ. Which of the following is the correct option?

Updated On: Mar 16, 2025
  • 𝛼 = 7, 𝛽 = βˆ’1, 𝛾 = βˆ’2
  • 𝛼 = βˆ’7, 𝛽 = βˆ’1, 𝛾 = βˆ’2
  • 𝛼 = 7, 𝛽 = βˆ’1, 𝛾 = 2
  • 𝛼 = βˆ’7, 𝛽 = 1, 𝛾 = βˆ’2
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is A

Solution and Explanation

The dimensions of Young's modulus of elasticity (π‘Œ) are [𝑀][𝐿]⁻¹[𝑇]⁻², where [𝑀] represents mass, [𝐿] represents length, and [𝑇] represents time. 
Let's analyze the dimensions of each derived quantity: 
The speed of light (𝑐) has dimensions [𝐿][𝑇]⁻¹. 
Planck's constant (β„Ž) has dimensions [𝑀][𝐿]Β²[𝑇]⁻¹. 
The gravitational constant (𝐺) has dimensions [𝑀]⁻¹[𝐿]Β³[𝑇]⁻².
Substituting the dimensions of 𝑐, β„Ž, and 𝐺 into the expression π‘Œ = π‘π›Όβ„Žπ›½πΊπ›Ύ, we have: 
[𝑀][𝐿]⁻¹[𝑇]⁻² = ([𝐿][𝑇]⁻¹)Ξ±([𝑀][𝐿]Β²[𝑇]⁻¹)Ξ²([𝑀]⁻¹[𝐿]Β³[𝑇]⁻²)Ξ³
By equating the dimensions on both sides of the equation, we can set up the following equations: 
For mass dimension: 1 = 0 + Ξ² - Ξ³. 
For length dimension: -1 = 1Ξ± + 2Ξ² + 3Ξ³. 
For time dimension: -2 = -1Ξ± - Ξ² - 2Ξ³. 
Solving these equations simultaneously will allow us to determine the values of 𝛼, 𝛽, and 𝛾. 
Solving the equations, we find that 𝛼 = 7, 𝛽 = -1, and 𝛾 = -2. 
Therefore, the correct option is (A) 𝛼 = 7, 𝛽 = -1, 𝛾 = -2.

Was this answer helpful?
26
15

Top Questions on Youngs double slit experiment

View More Questions

Questions Asked in JEE Advanced exam

View More Questions