The dimensions of Young's modulus of elasticity (π) are [π][πΏ]β»ΒΉ[π]β»Β², where [π] represents mass, [πΏ] represents length, and [π] represents time.
Let's analyze the dimensions of each derived quantity:
The speed of light (π) has dimensions [πΏ][π]β»ΒΉ.
Planck's constant (β) has dimensions [π][πΏ]Β²[π]β»ΒΉ.
The gravitational constant (πΊ) has dimensions [π]β»ΒΉ[πΏ]Β³[π]β»Β².
Substituting the dimensions of π, β, and πΊ into the expression π = ππΌβπ½πΊπΎ, we have:
[π][πΏ]β»ΒΉ[π]β»Β² = ([πΏ][π]β»ΒΉ)Ξ±([π][πΏ]Β²[π]β»ΒΉ)Ξ²([π]β»ΒΉ[πΏ]Β³[π]β»Β²)Ξ³.
By equating the dimensions on both sides of the equation, we can set up the following equations:
For mass dimension: 1 = 0 + Ξ² - Ξ³.
For length dimension: -1 = 1Ξ± + 2Ξ² + 3Ξ³.
For time dimension: -2 = -1Ξ± - Ξ² - 2Ξ³.
Solving these equations simultaneously will allow us to determine the values of πΌ, π½, and πΎ.
Solving the equations, we find that πΌ = 7, π½ = -1, and πΎ = -2.
Therefore, the correct option is (A) πΌ = 7, π½ = -1, πΎ = -2.
The center of a disk of radius $ r $ and mass $ m $ is attached to a spring of spring constant $ k $, inside a ring of radius $ R>r $ as shown in the figure. The other end of the spring is attached on the periphery of the ring. Both the ring and the disk are in the same vertical plane. The disk can only roll along the inside periphery of the ring, without slipping. The spring can only be stretched or compressed along the periphery of the ring, following Hookeβs law. In equilibrium, the disk is at the bottom of the ring. Assuming small displacement of the disc, the time period of oscillation of center of mass of the disk is written as $ T = \frac{2\pi}{\omega} $. The correct expression for $ \omega $ is ( $ g $ is the acceleration due to gravity): 
Let $ a_0, a_1, ..., a_{23} $ be real numbers such that $$ \left(1 + \frac{2}{5}x \right)^{23} = \sum_{i=0}^{23} a_i x^i $$ for every real number $ x $. Let $ a_r $ be the largest among the numbers $ a_j $ for $ 0 \leq j \leq 23 $. Then the value of $ r $ is ________.