Let I=∫x log 2x dx
Taking log 2x as first function and x as second function and integrating by parts, we obtain
I = log 2x∫x dx-∫{(\(\frac {d}{dx} 2log \ x\))∫x dx} dx
I = log 2x . \(\frac {x^2}{2}\) - ∫\(\frac {2}{2x}\) . \(\frac {x^2}{2}\)dx
I = \(\frac {x^2log\ 2x}{2}\) - ∫\(\frac {x}{2}\)dx
I = \(\frac {x^2log\ 2x}{2}\) - \(\frac {x^2}{4}\) + C
Let \( f : (0, \infty) \to \mathbb{R} \) be a twice differentiable function. If for some \( a \neq 0 \), } \[ \int_0^a f(x) \, dx = f(a), \quad f(1) = 1, \quad f(16) = \frac{1}{8}, \quad \text{then } 16 - f^{-1}\left( \frac{1}{16} \right) \text{ is equal to:}\]

A ladder of fixed length \( h \) is to be placed along the wall such that it is free to move along the height of the wall.
Based upon the above information, answer the following questions:
(iii) (b) If the foot of the ladder, whose length is 5 m, is being pulled towards the wall such that the rate of decrease of distance \( y \) is \( 2 \, \text{m/s} \), then at what rate is the height on the wall \( x \) increasing when the foot of the ladder is 3 m away from the wall?
The number of formulas used to decompose the given improper rational functions is given below. By using the given expressions, we can quickly write the integrand as a sum of proper rational functions.

For examples,
