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Remember Markovnikov’s rule for electrophilic addition reactions. The most stable carbocation intermediate leads to the major product.

Updated On: Jan 10, 2025
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The Correct Option is B

Solution and Explanation

Step 1: Identify the Reactants
The reactants are tetrahydrofuran (THF) and 2-methylpropene. The reaction is catalyzed by HF and takes place under heat. 
Step 2: Determine the Reaction Mechanism
This reaction is an electrophilic addition of THF to the alkene. HF protonates the alkene to form a carbocation. The oxygen in THF acts as a nucleophile and attacks the carbocation. Finally, deprotonation occurs to yield the product.
Step 3: Determine the Major Product
The major product is determined by Markovnikov’s rule, which states that the proton adds to the carbon of the double bond with more hydrogens. In this case, the carbocation will form on the more substituted carbon of 2-methylpropene, leading to product (1).

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Concepts Used:

Hydrocarbons

Hydrocarbons can be described as organic compounds that consists only hydrogen and carbon atoms. These compounds are of different types and thereby have distinct natures. Hydrocarbons are colorless gases and are known for discharging faint odours. These have been categorized under four major classes named as alkynes, alkanes, alkenes, and aromatic hydrocarbons. 

Types of Hydrocarbons

  1. Saturated hydrocarbons - Saturated hydrocarbons are those compounds where there is a single bond exists between carbon atoms and are saturated with atoms of hydrogen.
  2. Unsaturated hydrocarbons - Hydrocarbons comprises of at least one double or triple bond between carbon atoms are known as unsaturated hydrocarbons.
  3. Aliphatic hydrocarbons - The term denotes the hydrocarbons formed as an outcome of the chemical degradation of fats. Aliphatic hydrocarbons are basically chemical compounds.
  4. Aromatic hydrocarbons - They are distinguished because of the presence of benzene rings in them. They give away distinct types of aroma. These hydrocarbons comprises of only hydrogen and carbon atoms.