Question:

$\displaystyle\lim_{x \to \infty} \frac{ (2x -3)(3x -4)}{(4x - 5)(5x - 6)}$ is equal to:

Updated On: Jul 6, 2022
  • $ \frac{1}{10}$
  • 0
  • $ \frac{1}{5}$
  • $ \frac{3}{10}$
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The Correct Option is D

Solution and Explanation

Let $f(x) = \frac{ (2x -3)(3x -4)}{(4x - 5)(5x - 6)}$ we have to find $\displaystyle\lim_{x \to \infty} f(x)$ Put $ x = \frac{1}{h},$ if $x \to \infty ,h \to 0$ then $\displaystyle\lim_{x \to \infty} f(x) = \displaystyle\lim_{h \to 0} \frac{ (2x -3h)(3x -4h)}{(4x - 5h)(5x - 6h)}$ $ = \frac{6}{20} = \frac{3}{10}$
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