Question:

$\displaystyle\lim_{x\to \frac{\pi}{2}} \frac{\cos \, x}{ x - \frac{\pi}{2}}$ equals:

Updated On: Jul 6, 2022
  • -6
  • -1
  • $\pi$
  • $ - \pi $
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The Correct Option is B

Solution and Explanation

Let $ f(x ) = \displaystyle\lim_{x\to \frac{\pi}{2}} \frac{\cos \, x}{ x - \frac{\pi}{2}}$ Put $x - \frac{\pi}{2} = h$ When $x \to \pi /2 , h \to 0$ $ \therefore \:\:\: \displaystyle\lim_{h \to 0} \frac{\cos \left(\frac{\pi}{2} + h \right)}{h} = - \displaystyle\lim_{h \to 0} \frac{ \sin \, h }{h} = -1$
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