Question:
$(x^2 + 1)2dy + (y(2x^3 + x) – 2)dx = 0, y(0) = 0,$ then y(2) is equal to
$(x^2 + 1)2dy + (y(2x^3 + x) – 2)dx = 0, y(0) = 0,$ then y(2) is equal to
Updated On: Apr 5, 2024
- $\frac{2}5 tan^{-1}2 $
- $\frac{3}5 tan^{-1}2 $
- $\frac{2}5 tan^{-1}3$
- $\frac{3}5 tan^{-1}3 $
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The Correct Option is A
Solution and Explanation
The Correct answer is option(A) : $\frac{2}5 tan^{-1}2 $
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