\(\int x^2\bigg(1-\frac{1}{x}\bigg)dx\)
= \(\int (x^2-1)dx\)
\(= \int x^2dx-\int 1dx\)
=\(\frac{x^3}{3}-x+C\)
What is the Planning Process?
The representation of the area of a region under a curve is called to be as integral. The actual value of an integral can be acquired (approximately) by drawing rectangles.
Also, F(x) is known to be a Newton-Leibnitz integral or antiderivative or primitive of a function f(x) on an interval I.
F'(x) = f(x)
For every value of x = I.
Integral calculus helps to resolve two major types of problems: