a1 = 3, an = 3an-1 +2 for all n>1
⇒ a2 = 3a1 + 2 = 3(3) + 2 = 11
a3 = 3a2 +2 = 3(11) + 2 =35
a4 = 3a3+2 = 3(35) + 2 = 107
a5 = 3a4+2 = 3(107) + 2 = 323
Hence, the first five terms of the sequence are 3, 11, 35, 107, and 323.
The corresponding series is 3 + 11 + 35 + 107 + 323 + ….
Find the mean deviation about the mean for the data 38, 70, 48, 40, 42, 55, 63, 46, 54, 44.