Question:

Write Lewis symbols for the following atoms and ions: \(S\) and \(S ^{2-}\) ; \(Al\) and \(Al ^{3+}\) ; \(H\) and \(H ^-\)

Updated On: Nov 17, 2023
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Solution and Explanation

(i) \(S\) and \(S ^{2-}\) 
The number of valence electrons in \(sulphur\) is \(6\)
The Lewis dot symbol of \(sulphur\) \((S)\) is . The Lewis dot symbol of sulphur
The dinegative charge infers that there will be two electrons more in addition to the six valence electrons. 
Hence, the Lewis dot symbol of \(S ^{2-}\) is . the Lewis dot symbol of S2-


(ii) \(Al\) and \(Al ^{3+}\) 
The number of valence electrons in \(aluminium\) is \(3\).
The Lewis dot symbol of \(aluminium\) \((Al)\) is . The Lewis dot symbol of Al
The tripositive charge on a species infers that it has donated its three electrons. 
Hence, the Lewis dot symbol is the Lewis dot symbol of Al3+


(iii) \(H\) and \(H ^-\) 
The number of valence electrons in \(hydrogen\) is \(1\).
The Lewis dot symbol of \(hydrogen\) \((H)\) is  The Lewis dot symbol of hydrogen
The uninegative charge infers that there will be one electron more in addition to the one valence electron. 
Hence, the Lewis dot symbol is the Lewis dot symbol of H-

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