Question

Write ions produced in an aqueous solution of \( K_4[Fe(CN)_6] \). What is the oxidation number of \( Fe \) in this compound?

Hint:

The oxidation state of the central metal ion is calculated by balancing the charge of the complex ion.

Answer 1

- In aqueous solution, \( K_4[Fe(CN)_6] \) dissociates as: \[ K_4[Fe(CN)_6] \rightarrow 4K^+ + [Fe(CN)_6]^{4-}. \] - Oxidation number of \( Fe \) in \( [Fe(CN)_6]^{4-} \) is \( +2 \): \[ x + (-1 \times 6) = -4 \quad \Rightarrow \quad x = +2. \]