Write down a unit vector in plane,making an angle of \(30°\)with the positive direction of \(x-axis.\)
If \(\vec{r}\) is a unit vector in the \(XY-\)plane,then \(\vec{r}=cosθ\hat{i}+sinθ\hat{j}.\)
Here,θ is the angle made by the unit vector with the positive direction of the \(x-axis.\)
Therefore,for \(θ=30°:\)
\(\vec{r}=cos30^{\degree}\hat{i}+sin30^{\degree}\hat{j}={\frac{\sqrt{3}}{2}}\hat{i}+\frac{1}{2}\hat{j}\)
Hence,the required unit vector is \({\frac{\sqrt{3}}{2}}\hat{i}+\frac{1}{2}\hat{j}\).
Let \( \vec{a} \) and \( \vec{b} \) be two co-initial vectors forming adjacent sides of a parallelogram such that:
\[
|\vec{a}| = 10, \quad |\vec{b}| = 2, \quad \vec{a} \cdot \vec{b} = 12
\]
Find the area of the parallelogram.
Draw a rough sketch for the curve $y = 2 + |x + 1|$. Using integration, find the area of the region bounded by the curve $y = 2 + |x + 1|$, $x = -4$, $x = 3$, and $y = 0$.
A school is organizing a debate competition with participants as speakers and judges. $ S = \{S_1, S_2, S_3, S_4\} $ where $ S = \{S_1, S_2, S_3, S_4\} $ represents the set of speakers. The judges are represented by the set: $ J = \{J_1, J_2, J_3\} $ where $ J = \{J_1, J_2, J_3\} $ represents the set of judges. Each speaker can be assigned only one judge. Let $ R $ be a relation from set $ S $ to $ J $ defined as: $ R = \{(x, y) : \text{speaker } x \text{ is judged by judge } y, x \in S, y \in J\} $.