Question:

Write chemical equation of the reaction of glucose with (i) Hydroxylamine, and (ii) Bromine water.

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Remember: Glucose behaves like an aldehyde, so it reacts with reagents like hydroxylamine and bromine water that test aldehyde functionality.
Updated On: Oct 7, 2025
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Solution and Explanation

(i) Reaction of glucose with hydroxylamine:
Glucose reacts with hydroxylamine (\(NH_2OH\)) to form an oxime by reacting with the aldehyde group (-CHO) of glucose. \[ C_6H_{12}O_6 + NH_2OH \longrightarrow C_6H_{11}O_6{-}CH{=}NOH + H_2O \] (ii) Reaction of glucose with bromine water:
Glucose undergoes mild oxidation with bromine water, converting the aldehyde group (-CHO) into a carboxylic acid (-COOH), giving gluconic acid. \[ C_6H_{12}O_6 + Br_2 + H_2O \longrightarrow C_6H_{12}O_7 + 2HBr \] Conclusion:
- With hydroxylamine, glucose forms an oxime derivative.
- With bromine water, glucose is oxidized to gluconic acid.
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