At the moment of switching (\(t = 0^+\)), a capacitor cannot change its voltage instantaneously because:
\[
i_C = C \frac{dv}{dt}
\]
If there's an abrupt change in voltage, it would require infinite current, which is not physically possible. Instead, the capacitor behaves like a short circuit at \(t = 0^+\), allowing a surge of current as it charges or discharges.
As time progresses, the capacitor charges and gradually acts more like an open circuit in DC conditions.
Final Answer: (2) Short circuit