Question:

With some initial change at \(t = 0^+\), a capacitor will act as ________.

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At \(t = 0^+\), capacitor behaves like a short circuit; at steady state (DC), it behaves like an open circuit.
Updated On: Jun 23, 2025
  • Open circuit
  • Short circuit
  • A current source
  • A voltage source
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The Correct Option is B

Solution and Explanation

At the moment of switching (\(t = 0^+\)), a capacitor cannot change its voltage instantaneously because: \[ i_C = C \frac{dv}{dt} \] If there's an abrupt change in voltage, it would require infinite current, which is not physically possible. Instead, the capacitor behaves like a short circuit at \(t = 0^+\), allowing a surge of current as it charges or discharges.
As time progresses, the capacitor charges and gradually acts more like an open circuit in DC conditions. Final Answer: (2) Short circuit
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