Question:
If diode cut-in voltage is 0.6 V. The diode status are
If diode cut-in voltage is 0.6 V. The diode status are
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Compare source voltage differences with 0.6V cut-in to decide diode ON/OFF status.
Updated On: Jun 23, 2025
- only D1 on
- only D2 on
- both D1 & D2 on
- both D1 & D2 off
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The Correct Option is C
Solution and Explanation
Given:
- Left source = 6.4 V
- Right source = 6.8 V
- Middle node between 220Ω and 680Ω
Check forward bias condition:
- D1: \( 6.4 - 0.6 = 5.8 \) V → forward biased
- D2: \( 6.8 - 0.6 = 6.2 \) V → also forward biased
So, both diodes have sufficient voltage>0.6V → both are ON.
- Left source = 6.4 V
- Right source = 6.8 V
- Middle node between 220Ω and 680Ω
Check forward bias condition:
- D1: \( 6.4 - 0.6 = 5.8 \) V → forward biased
- D2: \( 6.8 - 0.6 = 6.2 \) V → also forward biased
So, both diodes have sufficient voltage>0.6V → both are ON.
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