Question:

With $17$ consonants and $5$ vowels the number of words of four letters that can be formed having two different vowels in the middle and one consonant, repeated or different at each end is

Updated On: Jun 3, 2023
  • 5780
  • 2890
  • 5440
  • 2720
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The Correct Option is A

Solution and Explanation

The two letters, the first and the last of the four lettered word can be chosen in $(17)^{2}$ ways, as repetition is allowed for consonants.
The two vowels in the middle are distinct so that the number of ways of filling up the two places is ${ }^{5} P_{2}=20$.
The no. of different words $=(17)^{2} \cdot 20=5780$.
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Concepts Used:

Sequences

A set of numbers that have been arranged or sorted in a definite order is called a sequence. The terms in a series mention the numbers in the sequence, and each term is distinguished or prominent from the others by a common difference. The end of the sequence is frequently represented by three linked dots, which specifies that the sequence is not broken and that it will continue further.

Read More: Sequence and Series

Types of Sequence:

There are four types of sequences such as: