The question asks which transition metal does not form an \( \text{MO} \) type oxide, where \( \text{M} \) is the transition metal. The candidates provided are \( V \), \( Cr \), \( Mn \), and \( Sc \). Each of these symbols represents a transition metal from the periodic table. Transition metals are known for forming various types of oxides, often affected by their oxidation states. The direct approach here is to determine the oxidation states and typical oxides formed by these metals:
1. Oxide Types:
- \( V \) (Vanadium): Typically forms oxides such as \( \text{VO} \), \( \text{V}_2\text{O}_3 \), \( \text{VO}_2 \), and \( \text{V}_2\text{O}_5 \), indicating it does form an \( \text{MO} \) type oxide.
- \( Cr \) (Chromium): Known to form \( \text{CrO} \), \( \text{Cr}_2\text{O}_3 \), and \( \text{CrO}_2, \) hence it does form an \( \text{MO} \) type oxide.
- \( Mn \) (Manganese): Can form oxides such as \( \text{MnO} \), \( \text{Mn}_2\text{O}_3 \), \( \text{MnO}_2 \), and \( \text{Mn}_2\text{O}_7, \) showing it forms an \( \text{MO} \) type oxide.
- \( Sc \) (Scandium): Forms \( \text{Sc}_2\text{O}_3 \) as its stable oxide and does not form a simple \( \text{MO} \) oxide.
2. Conclusion:
Among the given transition metals, Scandium (\( \text{Sc} \)) does not form an \( \text{MO} \) type oxide due to its limited oxidation state and specific oxide formation, which is \( \text{Sc}_2\text{O}_3 \). Therefore, the correct answer is \( \text{Sc} \).