Which statement is NOT correct for p-toluenesulphonyl chloride?
- It is known as Hinsberg’s reagent
- It is used to distinguish primary and secondary amines
- On treatment with secondary amine, it leads to a product, that is soluble in alkali
- It doesn’t react with tertiary amines
The Correct Option is C
Solution and Explanation
The correct answer is (C) : On treatment with secondary amine, it leads to a product, that is soluble in alkali
Top Questions on Amines
- Number of amine compounds from the following giving solids which are soluble in NaOH upon reaction with Hinsberg's reagent is _____.
- Number of compounds which give reaction with Hinsberg's reagent is_______.
- An amine $(\text{X})$ is prepared by ammonolysis of benzyl chloride. On adding $p$-toluenesulphonyl chloride to it, the solution remains clear.Molar mass of the amine $(\text{X})$ formed is _____ $\text{g mol}^{-1}$.(Given molar mass in $\text{g mol}^{-1}$: $\text{C} = 12, \, \text{H} = 1, \, \text{O} = 16, \, \text{N} = 14$)
- X of enthanamine was subjected to reaction with \(NaNO_2/HCl\) followed by hydrolysis to liberate \(N_2\) and HCl. The HCl generated was completely neutralised by 0.2 moles of NaOH. X is ____ g.
- Given below are two statements:
Statement (I) : All the following compounds react with p-toluenesulfonyl chloride.
$C_6H_5NH_2 \quad (C_6H_5)_2NH \quad (C_6H_5)_3N$
Statement (II) : Their products in the above reaction are soluble in aqueous NaOH.
In the light of the above statements, choose the correct answer from the options given below.
Questions Asked in JEE Main exam
- The coordination geometry around the manganese in decacarbonyldimanganese(0) is
- JEE Main - 2024
- coordination compounds
- Given below are two statements:
Statement (I) : The NH2 group in Aniline is ortho and para directing and a powerful activating group.
Statement (II) : Aniline does not undergo Friedel- Craft’s reaction (alkylation and acylation). In the light of the above statements
Choose the most appropriate answer from the options given below :- JEE Main - 2024
- Aromaticity & chemistry of aromatic compounds
- A rectangular loop of length 2.5 m and width 2 m is placed at 60° to a magnetic field of 4 T. The loop is removed from the field in 10 sec. The average emf induced in the loop during this time is:
- JEE Main - 2024
- Electromagnetic induction
- Two coils have mutual inductance 0.002 H. The current changes in the first coil according to the relation \( i = i_0 \sin \omega t \), where \( i_0 = 5 \, \text{A} \) and \( \omega = 50\pi \, \text{rad/s} \). The maximum value of emf in the second coil is \( \frac{\pi}{\alpha} \). The value of \( \alpha \) is ______.
- JEE Main - 2024
- Electromagnetic induction
- The 20th term from the end of the progression \[ 20, 19, \frac{1}{4}, \frac{1}{2}, \frac{3}{4}, \ldots, -129 \frac{1}{4} \] is:
- JEE Main - 2024
- Arithmetic Progression
Concepts Used:
Amines
Amine is a type of compound which is derived from ammonia (NH3). According to Organic chemistry, they are basically classified as the functional groups of the organic nitrogen compounds that contain nitrogen atoms with a lone pair.
Amine - Types
Primary Amines:
It is formed when one hydrogen atom in ammonia is substituted by an alkyl or aromatic group. Amino acids and methyl amine are the best examples that why aromatic amines include aniline.
Secondary Amines:
Amines that have two organic substitutes either alkyl or aryl ones or both and are bound to the nitrogen together with one hydrogen are termed as secondary amines. For Example, Dimethylamine.
Tertiary Amines:
Tertiary Amines are the amines where the nitrogen consists of three organic substitutes. For example, Trimethylamine and EDTA.