Question

Which one of the following statements is correct for electrolysis of brine solution?

• A. $OH ^{-}$is formed at cathode
• B. $Cl _2$ is formed at cathode
• C. $O _2$ is formed at cathode
• D. $H _2$ is formed at anode

Answer 1

The Correct Option is A

Electrolysis of brine solution
$NaCl(aq.)⟶N{a}_{(aq)}^{+}+C{l}_{\text{(aq)}}^{+}$
At anode $:2C{l}_{\text{(aq.)}}^{+}⟶\underset{\text{(Major)}}{C{l}_2(g)+2e^{-}}$
$2H_2{O}_{(\ell )}⟶\underset{\text{Minor}}{O_{2(g)}}+4H_{(aq)}^{+}+4e^{-}$
At Cathode : $2H_2{O}_{(\ell )}+2e^{-}⟶H_{2(g)}\uparrow +2O{H}_{(aq)}^{-}$
$2N{a}^{+}+2O{H}^{-}⟶2NaOH$

So, the correct option is (A): \(OH^−\) is formed at cathode.