The correct statement regarding the electric field due to static charges is that it is conservative and field lines do not form closed loops.
An electric field is said to be conservative if the work done by the electric field on a test charge is independent of the path taken and depends only on the initial and final positions. This implies that the work done around any closed path is zero, a property of a conservative field. Mathematically, for a conservative field, we have:
\(∮C E · dl = 0\)
where ∮C indicates the integral around a closed path and E is the electric field. Therefore, the electric field created by static charges is conservative.
Additionally, the electric field lines of static charges start at positive charges and end at negative charges, without forming closed loops. This is in contrast to the magnetic field lines, which do form closed loops. Therefore, the statement that the electric field is conservative and field lines do not form closed loops is correct.
The magnitude of heat exchanged by a system for the given cyclic process ABC (as shown in the figure) is (in SI units):

As shown below, bob A of a pendulum having massless string of length \( R \) is released from \( 60^\circ \) to the vertical. It hits another bob B of half the mass that is at rest on a frictionless table in the center. Assuming elastic collision, the magnitude of the velocity of bob A after the collision will be (take \( g \) as acceleration due to gravity):


Bittu and Chintu were partners in a firm sharing profit and losses in the ratio of 4 : 3. Their Balance Sheet as at 31st March, 2024 was as follows:
On 1st April, 2024, Diya was admitted in the firm for \( \frac{1}{7} \)th share in the profits on the following terms:
Prepare Revaluation Account and Partners' Capital Accounts.