Question:
Which one of the following reactions is not feasible?
Which one of the following reactions is not feasible?
Show Hint
For displacement reactions involving halogens, higher halogens oxidize lower ones, but lower halogens cannot oxidize higher ones.
Updated On: Jun 5, 2025
- \( Cl_2(g) + 2KBr(aq) \longrightarrow 2KCl(aq) + Br_2(l) \)
- \( Cl_2(g) + 2KI(aq) \longrightarrow 2KCl(aq) + I_2(s) \)
- \( Br_2(l) + 2KI(aq) \longrightarrow 2KBr(aq) + I_2(s) \)
- \( I_2(s) + 2KBr(aq) \longrightarrow 2KI(aq) + Br_2(l) \)
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Verified By Collegedunia
The Correct Option is D
Solution and Explanation
Step 1: Understanding Feasibility
Feasibility depends on oxidation strength:
- Chlorine is the strongest oxidizing agent, capable of replacing bromine and iodine.
- Bromine is weaker, but can replace iodine.
- Iodine is the weakest and cannot oxidize bromide ions.
Step 2: Evaluating the Reactions
- (A) \( Cl_2 + 2KBr \rightarrow 2KCl + Br_2 \):
- Feasible (Chlorine displaces bromine).
- (B) \( Cl_2 + 2KI \rightarrow 2KCl + I_2 \):
- Feasible (Chlorine displaces iodine).
- (C) \( Br_2 + 2KI \rightarrow 2KBr + I_2 \):
- Feasible (Bromine displaces iodine).
- (D) \( I_2 + 2KBr \rightarrow 2KI + Br_2 \):
- Not feasible (Iodine cannot displace bromine).
Conclusion
Thus, the correct answer is:
\[
I_2(s) + 2KBr(aq) \longrightarrow 2KI(aq) + Br_2(l)
\]
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