Question:
Which one of the following reactions is not feasible?
Which one of the following reactions is not feasible?
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For displacement reactions involving halogens, higher halogens oxidize lower ones, but lower halogens cannot oxidize higher ones.
Updated On: Jun 5, 2025
- \( Cl_2(g) + 2KBr(aq) \longrightarrow 2KCl(aq) + Br_2(l) \)
- \( Cl_2(g) + 2KI(aq) \longrightarrow 2KCl(aq) + I_2(s) \)
- \( Br_2(l) + 2KI(aq) \longrightarrow 2KBr(aq) + I_2(s) \)
- \( I_2(s) + 2KBr(aq) \longrightarrow 2KI(aq) + Br_2(l) \)
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Verified By Collegedunia
The Correct Option is D
Solution and Explanation
Step 1: Understanding Feasibility
Feasibility depends on oxidation strength:
- Chlorine is the strongest oxidizing agent, capable of replacing bromine and iodine.
- Bromine is weaker, but can replace iodine.
- Iodine is the weakest and cannot oxidize bromide ions.
Step 2: Evaluating the Reactions
- (A) \( Cl_2 + 2KBr \rightarrow 2KCl + Br_2 \):
- Feasible (Chlorine displaces bromine).
- (B) \( Cl_2 + 2KI \rightarrow 2KCl + I_2 \):
- Feasible (Chlorine displaces iodine).
- (C) \( Br_2 + 2KI \rightarrow 2KBr + I_2 \):
- Feasible (Bromine displaces iodine).
- (D) \( I_2 + 2KBr \rightarrow 2KI + Br_2 \):
- Not feasible (Iodine cannot displace bromine).
Conclusion
Thus, the correct answer is:
\[
I_2(s) + 2KBr(aq) \longrightarrow 2KI(aq) + Br_2(l)
\]
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