Step 1: Acidity of carboxylic acids depends on the stability of the carboxylate ion formed after loss of a proton.
Step 2: Electron-withdrawing groups increase acidity by stabilizing the negative charge through the –I (inductive) effect.
Step 3: The inductive effect of halogens follows the order:
\[
\text{F}>\text{Cl}>\text{Br}>\text{CH}_3
\]
Step 4: CF\(_3\)COOH has the strongest electron-withdrawing effect, providing maximum stabilization to the conjugate base.
Step 5: Hence, CF\(_3\)COOH is the most acidic among the given compounds.