To solve this problem, we need to compare the acidity of phenol (C6H5OH), alcohol (ROH), and water (H2O).
1. Understanding Acid Strength:
Acid strength depends on the ability of the molecule to donate a proton (H+). This is determined by the stability of the conjugate base formed after proton loss.
2. Phenol (C6H5OH) vs Alcohol (ROH):
Phenol is more acidic than alcohol because the negative charge on the oxygen in the phenoxide ion (C6H5O-) is stabilized by resonance with the aromatic ring. In contrast, the negative charge on the oxygen in the alkoxide ion (RO-) is not stabilized, making alcohol less acidic than phenol.
3. Phenol (C6H5OH) vs Water (H2O):
Water (H2O) is a weaker acid than phenol. Although water can donate a proton to form the hydroxide ion (OH-), the conjugate base of phenol is more stable due to resonance stabilization.
4. Conclusion:
The correct order of acid strength is: Water > Phenol > Alcohol.
Final Answer:
The correct option is (D) H2O > C6H5OH > ROH.
Simar, Tanvi, and Umara were partners in a firm sharing profits and losses in the ratio of 5 : 6 : 9. On 31st March, 2024, their Balance Sheet was as follows:
Liabilities | Amount (₹) | Assets | Amount (₹) |
Capitals: | Fixed Assets | 25,00,000 | |
Simar | 13,00,000 | Stock | 10,00,000 |
Tanvi | 12,00,000 | Debtors | 8,00,000 |
Umara | 14,00,000 | Cash | 7,00,000 |
General Reserve | 7,00,000 | Profit and Loss A/c | 2,00,000 |
Trade Payables | 6,00,000 | ||
Total | 52,00,000 | Total | 52,00,000 |
Umara died on 30th June, 2024. The partnership deed provided for the following on the death of a partner:
If \(\begin{vmatrix} 2x & 3 \\ x & -8 \\ \end{vmatrix} = 0\), then the value of \(x\) is: