Step 1: Understanding Colligative Properties
- Colligative properties depend on the number of particles in the solution rather than their nature.
- The van't Hoff factor (\(i\)) represents the number of ions each molecule dissociates into.
Step 2: Calculating the Number of Ions
BaCl$_2$ dissociates into 3 ions: Ba$^{2+}$ and 2Cl$^-$.
AgNO$_3$ dissociates into 2 ions: Ag$^+$ and NO$_3^-$.
Urea does not dissociate, so \( i = 1 \).
(NH$_4$)$_3$PO$_4$ dissociates into 4 ions: 3 NH$_4^+$ and 1 PO$_4^{3-}$.
Step 3: Identifying the Substance with the Highest Colligative Property
The greater the number of ions, the higher the colligative properties.
Since (NH$_4$)$_3$PO$_4$ produces 4 ions, it exhibits the highest colligative effect.
Thus, the correct answer is (D).