To analyze the problem, we consider two properties:
Analysis of the given species:
Conclusion: Among the given options, only MnO2−4 exhibits both LMCT and paramagnetism due to the presence of one unpaired electron and the ability of oxygen ligands to transfer charge to Mn. Therefore, the correct answer is: 2. MnO2−4.
Match the following:
Ions | Properties |
I. Zn2+ | i. d8 configuration |
II. Cu2+ | ii. Colourless |
III. Ni2+ | iii. µ = 1.73 BM |
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