Question:

Which of the following species exhibits both LMCT and paramagnetism?

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Paramagnetism arises from unpaired electrons, while LMCT involves electron transfer between ligand and metal.
Updated On: Jan 10, 2025
  • MnO4
  • MnO2−4
  • Cr2O2−7
  • CrO2−4
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The Correct Option is B

Solution and Explanation

To analyze the problem, we consider two properties:

  • Ligand-to-Metal Charge Transfer (LMCT): LMCT occurs when there is a transfer of electrons from the ligand (oxygen) to the metal ion (Mn or Cr) due to a significant energy difference between the ligand and metal orbitals.
  • Paramagnetism: Paramagnetic species have unpaired electrons in their electronic configuration.

Analysis of the given species:

  • MnO4 (Permanganate ion): In MnO4, Mn is in the +7 oxidation state with no unpaired electrons (electronic configuration: 3d0). This species shows LMCT but is diamagnetic.
  • MnO2−4 (Manganate ion): In MnO2−4, Mn is in the +6 oxidation state with one unpaired electron (electronic configuration: 3d1). This species exhibits both LMCT and paramagnetism.
  • Cr2O2−7 (Dichromate ion): In Cr2O2−7, Cr is in the +6 oxidation state with no unpaired electrons (electronic configuration: 3d0). This species is diamagnetic and shows LMCT.
  • CrO2−4 (Chromate ion): In CrO2−4, Cr is also in the +6 oxidation state with no unpaired electrons. This species shows LMCT but is diamagnetic.

Conclusion: Among the given options, only MnO2−4 exhibits both LMCT and paramagnetism due to the presence of one unpaired electron and the ability of oxygen ligands to transfer charge to Mn. Therefore, the correct answer is: 2. MnO2−4.

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