Question:

Which of the following pair of molecules contain odd electron molecule and an expanded octet molecule?

Updated On: Nov 19, 2024
  • BCl3 and SF6

  • NO and H2SO4

  • SF6 and H2SO4

  • BCl3 and NO

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The Correct Option is B

Solution and Explanation

NO is an odd electron species as N has 5 valence electrons and O has 6 valence electrons. Thus overall 1 electron on N remains unpaired.
S in H2SO4 has an expanded octet thus H2SO4 is expanded octet molecule.
So, the correct option is (B): NO and H2SO4

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Concepts Used:

Bond Parameters

Covalent bonds can be characterized on the basis of several bond parameters such as bond length, bond angle, bond order, and bond energy (also known as bond enthalpy). These bond parameters offer insight into the stability of a chemical compound and the strength of the chemical bonds holding its atoms together.

Bond parameters 

  • Bond length: it is an equilibrium distance between the centres of the nuclei of the two bonded atoms. It is expressed in terms of A.
  • Bond Angle: It is characterized as the point between the orbitals consisting of holding electron sets around the focal iota in an atom/complex particle. Bond points are communicated in degrees which are tentatively controlled by spectroscopic strategies.
  • Bond Enthalpy: the measure of energy needed to break one mole of obligations of a specific sort between two molecules in a vaporous state. The unit of bond enthalpy is kJ mol–1. The more the bond enthalpy, the more grounded the bond is.

For example, The H—H bond enthalpy in hydrogen is 435.8 kJ mol-1. \

  • Bond Order: According to Lewis, Bond Order is given by the number of connections between the two atoms in a particle.

Bond order of H2 (H —H) =1
Bond order of 02 (O = O) =2
Bond order of N2 (N = N) =3

  • Resonance Structures: It is observed that there are many molecules whose behaviour cannot be explained by a single Lewis structure.

Read More: Chemical Bonding and Molecular Structure