The basicity of metal oxides depends on the electropositivity of the metal.
More electropositive metals tend to form more basic oxides because the \( M-O \) bond is more ionic, leading to the easy release of \( O^{2-} \) ions (which react with water to form \( OH^- \) ions, increasing basicity).
Let's analyze the given oxides:
- \( \text{Na}_2\text{O} \): Sodium (Na) is an alkali metal (Group 1), which are highly electropositive.
Its oxide is expected to be strongly basic.
\( \text{Na}_2\text{O} + \text{H}_2\text{O} \rightarrow 2\text{NaOH} \) (strong base).
- \( \text{MgO} \): Magnesium (Mg) is an alkaline earth metal (Group 2), which is less electropositive than alkali metals.
Its oxide is basic but less so than alkali metal oxides.
\( \text{MgO} + \text{H}_2\text{O} \rightarrow \text{Mg(OH)}_2 \) (weak base).
- \( \text{Al}_2\text{O}_3 \): Aluminum (Al) is a metalloid.
Its oxide is amphoteric, meaning it can react with both acids and bases.
It is not highly basic.
- \( \text{Cr}_2\text{O}_3 \): Chromium (Cr) is a transition metal.
Its oxide is also amphoteric.
It is not highly basic.
Comparing the electropositivity of the metals: Na is the most electropositive among Na, Mg, Al, and Cr.
Therefore, its oxide, \( \text{Na}_2\text{O} \), is expected to be the most basic.
The order of basicity generally follows the order of electropositivity of the metals:
\( \text{Na}>\text{Mg}>\text{Al} \approx \text{Cr} \) (in terms of oxide basicity).
Thus, \( \text{Na}_2\text{O} \) is the most basic oxide among the given options.