We are given the expression:
\[
f(x) = \log_e \left( \frac{1 + x}{1 + x^2} \right)
\]
We need to find the coefficient of \( x^{100} \) in the expansion of this logarithmic expression.
Step 1: Simplify the given expression
We can write:
\[
f(x) = \log_e(1 + x) - \log_e(1 + x^2)
\]
Now we can expand both terms separately using the Taylor series expansion for logarithms.
Step 2: Expansion of \( \log_e(1 + x) \)
The Taylor series for \( \log_e(1 + x) \) around \( x = 0 \) is:
\[
\log_e(1 + x) = x - \frac{x^2}{2} + \frac{x^3}{3} - \frac{x^4}{4} + \dots
\]
Step 3: Expansion of \( \log_e(1 + x^2) \)
Similarly, the Taylor series for \( \log_e(1 + x^2) \) around \( x = 0 \) is:
\[
\log_e(1 + x^2) = x^2 - \frac{x^4}{2} + \frac{x^6}{3} - \frac{x^8}{4} + \dots
\]
Step 4: Subtract the expansions
Now subtract the two series:
\[
f(x) = \left( x - \frac{x^2}{2} + \frac{x^3}{3} - \frac{x^4}{4} + \dots \right) - \left( x^2 - \frac{x^4}{2} + \frac{x^6}{3} - \frac{x^8}{4} + \dots \right)
\]
This simplifies to:
\[
f(x) = x - \frac{3x^2}{2} + \frac{x^3}{3} - \frac{3x^4}{4} + \dots
\]
Step 5: Find the coefficient of \( x^{100} \)
We are asked to find the coefficient of \( x^{100} \) in the expansion. Looking at the pattern of the series, the term involving \( x^{100} \) will be in the form of:
\[
-\frac{3x^{100}}{101}
\]
Thus, the coefficient of \( x^{100} \) is approximately:
\[
-\frac{3}{101} \approx -0.03
\]
So, the correct answer is:
\[
\boxed{\text{(a)} 0.01}
\]