Question

Which of the following is true in an SHM?

• A. PE is maximum at \( x = 0 \)
• B. KE is maximum at \( x = 0 \)
• C. PE is minimum at \( x = A \)
• D. KE is minimum at \( x = 0 \)

Hint:

In SHM, remember that at the equilibrium position (\( x = 0 \)), the kinetic energy is at its maximum, and at the extreme positions (\( x = A \)), the potential energy is at its maximum.

Answer 1

The Correct Option is B

In Simple Harmonic Motion (SHM), the kinetic energy (KE) and potential energy (PE) continuously interchange. - (A) PE is maximum at \( x = 0 \): This is incorrect. PE is maximum when the displacement is maximum, i.e., at \( x = A \), not when \( x = 0 \). - (B) KE is maximum at \( x = 0 \): This is correct. At \( x = 0 \) (the equilibrium position), the velocity is maximum, and thus the kinetic energy is also maximum. This is because the object is moving the fastest at this point. - (C) PE is minimum at \( x = A \): This is incorrect. PE is maximum at \( x = A \) because the displacement from equilibrium is greatest. - (D) KE is minimum at \( x = 0 \): This is incorrect. KE is maximum at \( x = 0 \) because the velocity is maximum at this point. Thus, KE is maximum at \( x = 0 \) is the correct statement.