Step 1: Understanding Disproportionation and Redox Reactions
A disproportionation reaction is a special type of redox reaction in which a single element undergoes both oxidation and reduction. In contrast, a normal redox reaction involves oxidation and reduction of different elements.
Step 2: Oxidation States Analysis
Let's analyze the oxidation states of phosphorus (P) and sulfur (S) in the reaction: \[ P_4 + 8SOCl_2 \rightarrow 4PCl_3 + 2S_2Cl_2 + 4SO_2 \] In elemental phosphorus (\( P_4 \)), P has an oxidation state of \( 0 \).
In phosphorus trichloride (\( PCl_3 \)), P has an oxidation state of \( +3 \).
In sulfur oxychloride (\( SOCl_2 \)), S has an oxidation state of \( +4 \).
In disulfur dichloride (\( S_2Cl_2 \)), S has an oxidation state of \( +2 \).
In sulfur dioxide (\( SO_2 \)), S has an oxidation state of \( +4 \).
Step 3: Identify the Nature of the Reaction
Phosphorus (\( P \)) is oxidized from \( 0 \) to \( +3 \).
Sulfur (\( S \)) is reduced from \( +4 \) to \( +2 \).
Since phosphorus only undergoes oxidation and sulfur only undergoes reduction, this is a simple redox reaction, NOT a disproportionation reaction.
Step 4: Verify Other Options
Option (A) involves phosphorus undergoing both oxidation and reduction, making it a disproportionation reaction.
Option (B) involves oxygen undergoing disproportionation from \( -1 \) to both \( -2 \) and \( 0 \).
Option (C) also shows disproportionation of phosphorus.