Question:

Which of the following is not correctly matched?

Updated On: Sep 14, 2022
  • $PCl_5$ - $sp^3d$ hybridisation
  • $PCl_3$ - $sp^3$ hybridisation
  • $PCl_{5}$ (solid) - $\left[PtCl_{4}\right]^{+} \left[PtCl_{6}\right]^{-}$
  • $PCl_5$ - brownish powder
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The Correct Option is C

Solution and Explanation

\(PCl_5\) is yellowish-white powder.

PCl5 is used as a chlorinating reagent. It is a colorless, water-sensitive, and moisture-sensitive solid. In the solid state, PCl5 exists as an ionic solid, [PCl4]+[PCl6]−. The cation, [PCl4]+ is tetrahedral and sp3 hybridized. The anion, [PCl6]− is octahedral and is sp3d2 hybridized.

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Concepts Used:

P-Block Elements

  • P block elements are those in which the last electron enters any of the three p-orbitals of their respective shells. Since a p-subshell has three degenerate p-orbitals each of which can accommodate two electrons, therefore in all there are six groups of p-block elements.
  • P block elements are shiny and usually a good conductor of electricity and heat as they have a tendency to lose an electron. You will find some amazing properties of elements in a P-block element like gallium. It’s a metal that can melt in the palm of your hand. Silicon is also one of the most important metalloids of the p-block group as it is an important component of glass.

P block elements consist of: