Question:

Which of the following integrals is un-bounded?

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When evaluating integrals, watch out for points where the integrand becomes infinite, as these often lead to unbounded integrals.
Updated On: Jun 16, 2025
  • \( \int_0^{\frac{\pi}{4}} \tan(x) \, dx \)
  • \( \int_0^{\infty} e^{-x} \, dx \)
  • \( \int_0^a \frac{1}{a - x} \, dx \)
  • \( \int_0^{\infty} x e^x \, dx \)
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The Correct Option is C

Solution and Explanation

The integral \( \int_0^a \frac{1}{a - x} \, dx \) is unbounded because as \( x \) approaches \( a \), the integrand tends to infinity. This creates a singularity at \( x = a \), making the integral unbounded.
For the other options, the integrals are bounded as they do not exhibit any singularities. Hence, the correct answer is option (3).
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