To determine which function is odd, we need to understand that a function \( f(x) \) is odd if it satisfies the condition \( f(-x) = -f(x) \) for all \( x \) in its domain. Let's evaluate the given options:
Option (a): \( f(x) = 2^{-xx} \)
Let \( f(x) = 2^{-(x^2)} \), a quadratic function, which can be rewritten as:
\( f(-x) = 2^{-((-x)^2)} = 2^{-(x^2)} = f(x) \)
Since \( f(-x) = f(x) \), this is an even function, not odd.
Option (b): \( f(x) = 2^{x-xxxx} \)
Assuming \( f(x) = 2^{x-x^4} \), let's check:
\( f(-x) = 2^{-x-(-x)^4} = 2^{-x-x^4} \)
We find that \( f(-x) \neq -f(x) \), as \( 2^{-x-x^4} \neq -2^{x-x^4} \); thus, it isn't odd.
Conclusion:
Both functions fail the odd function condition. Therefore, the answer is that neither (a) nor (b) is an odd function.