Question:

Which of the following $fcc$ structure contains cations in alternate tetrahedral voids?

Updated On: Jun 14, 2022
  • $NaCI$
  • $ZnS$
  • $ Na_2O $
  • $ CaF_2 $
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The Correct Option is B

Solution and Explanation

In ZnS, $ S^{2-} $ (sulphide ions) are present at fee positions giving four sulphide ions per unit cell. To comply with 1 : 1 stoichiometry, four $ Zn^{2+} $ ion must be present in four alternate tetrahedral voids out of eight tetrahedral voids present. In NaCI, $ Na^+ $ ions are present in octahedral voids
while in $ Na_2O , Na^+ $ ions are present in all its tetrahedral voids giving the desired 2:1 stoichiometry. In $ CaF_2 , Ca^{2+} $ ions occupies fee positions and all the tetrahedral voids are occupied by fluoride ion
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Concepts Used:

Solid State

Solids are substances that are featured by a definite shape, volume, and high density. In the solid-state, the composed particles are arranged in several manners. Solid-state, in simple terms, means "no moving parts." Thus solid-state electronic devices are the ones inclusive of solid components that don’t change their position. Solid is a state of matter where the composed particles are arranged close to each other. The composed particles can be either atoms, molecules, or ions. 

Solid State

Types of Solids:

Based on the nature of the order that is present in the arrangement of their constituent particles solids can be divided into two types;

  • Amorphous solids behave the same as super cool liquids due to the arrangement of constituent particles in short-range order. They are isotropic and have a broad melting point (range is about greater than 5°C).
  • Crystalline solids have a fixed shape and the constituent particles are arranged in a long-range order.