Question:

Which of the following equations does not have a real root?

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Equations involving negative square roots have complex roots, not real.
Updated On: May 31, 2025
  • \(x^2 = 0\)
  • \(2x - 1 = 3\)
  • \(x^2 + 1 = 0\)
  • \(x^3 + x^2 = 0\)
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The Correct Option is C

Solution and Explanation

Given:
We need to find which equation does not have a real root.

Step 1: Recall the condition for real roots of quadratic equation
For a quadratic equation \(ax^2 + bx + c = 0\), the roots are real if the discriminant \(D = b^2 - 4ac \geq 0\).

Step 2: Analyze the equation \(x^2 + 1 = 0\)
Here, \(a = 1\), \(b = 0\), and \(c = 1\).
Calculate discriminant:
\[ D = 0^2 - 4 \times 1 \times 1 = -4 \]

Step 3: Interpret the result
Since \(D = -4 < 0\), the equation has no real roots.

Final Answer:
\[ \boxed{x^2 + 1 = 0} \]
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