Which of the following molecule/species is most stable?
The Correct Option is C
Solution and Explanation
Step 1. Identify Aromatic Stability: The most stable species among the options will be the one that is aromatic as aromatic compounds exhibit additional stability due to delocalized π-electrons.
Step 2. Analyze Each Structure: Option (1): This structure satisfies Huckel’s rule (4n + 2) for aromaticity and has a planar conjugated ring structure, making it aromatic and stable. Other Options: Do not satisfy Huckel’s rule or are non-aromatic.
Step 3. Conclusion: Option (3) is the most stable due to its aromaticity.
Top Questions on Hydrocarbons
- Which of the following is an alkene?
- BITSAT - 2025
- Chemistry
- Hydrocarbons
Complete the following reactions by writing the structure of the main products:
- CBSE CLASS XII - 2025
- Chemistry
- Hydrocarbons
- Complete the following reactions by writing the structural formulae of ‘A’ and ‘B’:
(i) CH$_3$CH=CH$_2$ + HBr $\xrightarrow{\text{Peroxide}}$ ‘A’ $\xrightarrow{KOH}$ ‘B’
(ii) CH$_3$CH$_2$CHCl + alc. KOH $\xrightarrow{\Delta}$ ‘A’ $\xrightarrow{\text{H}_2\text{O}}$ ‘B’ (Main product)- CBSE CLASS XII - 2025
- Chemistry
- Hydrocarbons
- A halide with formula C6H13Br gave two isomeric alkenes A and B on dehydrobromination. On ozonolysis of mixture of A and B the following compounds were obtained: CH3COCH3, CH3CHO, CH3CH2CHO and (CH3)2CHCHO. The halide is:
- AP EAPCET - 2025
- Chemistry
- Hydrocarbons
- What is the molecular formula of alkane?
- TS POLYCET - 2025
- Chemistry
- Hydrocarbons
Questions Asked in JEE Main exam
- If the equation of the parabola with vertex $\left(\frac{3}{2},\, 3\right)$ and the directrix $x + 2y = 0$ is
$$ ax^2 + by^2 - cxy - 30x - 60y + 225 = 0, $$ then $\alpha + \beta + \gamma$ is equal to:- JEE Main - 2025
- Calculus
- In a first order decomposition reaction, the time taken for the decomposition of reactant to one fourth and one eighth of its initial concentration are $ t_1 $ and $ t_2 $ (s), respectively. The ratio $ t_1 / t_2 $ will be:
- JEE Main - 2025
- Chemical Kinetics
- HA $ (aq) \rightleftharpoons H^+ (aq) + A^- (aq) $ The freezing point depression of a 0.1 m aqueous solution of a monobasic weak acid HA is 0.20 °C. The dissociation constant for the acid is Given: $ K_f(H_2O) = 1.8 \, \text{K kg mol}^{-1} $, molality ≡ molarity
- JEE Main - 2025
- Colligative Properties
20 mL of sodium iodide solution gave 4.74 g silver iodide when treated with excess of silver nitrate solution. The molarity of the sodium iodide solution is _____ M. (Nearest Integer value) (Given : Na = 23, I = 127, Ag = 108, N = 14, O = 16 g mol$^{-1}$)
- JEE Main - 2025
- Stoichiometry and Stoichiometric Calculations
- Which of the following binary mixture does not show the behavior of minimum boiling azeotropes?
- JEE Main - 2025
- Solutions