When ammonium nitrate \((NH_4NO_3)\) is heated, it decomposes to form nitrous oxide \((N_2O)\), water, and nitrogen dioxide:
\(2 NH_4NO_3 → 2 N_2O + 4 H_2O + O_2\)
This reaction is a classic example of the decomposition of ammonium nitrate on heating, producing \(N_2O\) (nitrous oxide), which is also known as laughing gas.
The correct answer is (B) : \(NH_4NO_3\).
1. Consider the decomposition reactions of the given compounds
- Pb(NO3)2 (Lead(II) nitrate): Upon heating, lead(II) nitrate decomposes to give lead(II) oxide (PbO), nitrogen dioxide (NO2), and oxygen (O2).
$$
2Pb(NO_3)_2(s) \rightarrow 2PbO(s) + 4NO_2(g) + O_2(g)
$$
- NH4NO3 (Ammonium nitrate): Upon heating, ammonium nitrate decomposes to give dinitrogen monoxide (N2O) and water (H2O).
$$
NH_4NO_3(s) \rightarrow N_2O(g) + 2H_2O(g)
$$
- NH4NO2 (Ammonium nitrite): Upon heating, ammonium nitrite decomposes to give nitrogen gas (N2) and water (H2O).
$$
NH_4NO_2(s) \rightarrow N_2(g) + 2H_2O(g)
$$
- NaNO3 (Sodium nitrate): Upon heating, sodium nitrate decomposes to give sodium nitrite (NaNO2) and oxygen (O2).
$$
2NaNO_3(s) \rightarrow 2NaNO_2(s) + O_2(g)
$$
2. Identify the compound that produces N2O upon heating
From the above decomposition reactions, we can see that ammonium nitrate ($NH_4NO_3$) produces dinitrogen monoxide ($N_2O$) upon heating.
Final Answer:
(B) $NH_4NO_3$
You are given a dipole of charge \( +q \) and \( -q \) separated by a distance \( 2l \). A sphere 'A' of radius \( R \) passes through the centre of the dipole as shown below and another sphere 'B' of radius \( 2R \) passes through the charge \( +q \). Then the electric flux through the sphere A is