In the given logic gate diagram:
- Two NOT gates are applied to the inputs.
- Their outputs are fed into an OR gate.
This configuration corresponds to:
\[
\overline{A} + \overline{B}
\]
Using De Morgan’s theorem:
\[
\overline{A} + \overline{B} = \overline{AB}
\]
Taking the complement again (which is not shown here, so this is the output itself), this is equivalent to the NAND operation inverted, hence it's:
\[
\overline{\overline{A} + \overline{B}} = AB
\]
So, the final result is \( AB \), which is the output of an AND gate.