Question:

Which element shows the lower oxidation state in the 3d series?

Show Hint

Zinc exhibits a \( +2 \) oxidation state due to its filled \( d^{10} \)-orbitals, making it unique in the 3d series.
Updated On: Jan 16, 2025
  • Scandium (Sc)
  • Titanium (Ti)
  • Zinc (Zn)
  • None of the above
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is C

Solution and Explanation

Zinc (\( \text{Zn} \)) in the 3d series of transition elements exhibits a lower oxidation state. Unlike other transition elements, which commonly show variable oxidation states due to their partially filled \( d \)-orbitals, zinc has a completely filled \( d^{10} \)-orbital configuration.
Electronic Configuration of Zn: \[ \text{Zn: } [\text{Ar}] 3d^{10} 4s^2 \] Since the \( 3d \)-orbitals are fully filled, zinc typically shows an oxidation state of \( +2 \) due to the loss of its two \( 4s \)-electrons, which is lower compared to other elements in the 3d series. Conclusion: Zinc shows the lowest oxidation state compared to other elements in the 3d series.
Was this answer helpful?
0
0