Step 1: Identify the structure. The compound is CH$_3$CH(OH)CH$_3$, an alcohol with -OH group.
Step 2: Count carbons:
- Total 3 carbons: CH$_3$-CH-CH$_3$ (OH on middle carbon).
Step 3: Name the parent chain: 3 carbons = propane. The -OH group is on the 2nd carbon, so it's propan-2-ol.
Step 4: Verify:
- Propan-1-ol: OH on 1st carbon.
- Ethanol: 2 carbons.
- Butan-2-ol: 4 carbons.
Matches option (2).
Identify the products R and S in the reaction sequence given.

For the reaction \( A + B \to C \), the rate law is found to be \( \text{rate} = k[A]^2[B] \). If the concentration of \( A \) is doubled and \( B \) is halved, by what factor does the rate change?