Question:

Identify the products R and S in the reaction sequence given. 

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Alkoxide formation followed by alkylation and hydrolysis typically leads to halide substitution and an alcohol byproduct.
Updated On: Mar 11, 2025
  • \( (CH_3)_3Cl, CH_3OH \)
  • \( (CH_3)_3COH, CH_3I \)
  • \( (CH_3)_3COH, CH_3OH \)
  • \( (CH_3)_2C=CH_2, CH_3OH \)
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The Correct Option is A

Solution and Explanation

Step 1: Understanding the Reaction Sequence
- The starting compound is tert-butanol \((CH_3)_3COH\).
- The first step involves reaction with Na, converting it into the sodium alkoxide \((CH_3)_3CO^-Na^+\) (P).
- The second step involves treatment with CH\(_3\)Br, leading to an alkylation reaction forming \((CH_3)_3CBr\) (Q).
- In the final step, hydrolysis with HI results in substitution of Br by Cl, giving \( (CH_3)_3Cl \), and an additional byproduct CH\(_3\)OH. Step 2: Identifying the Products - The final products obtained are \( (CH_3)_3Cl \) (tert-butyl chloride) and \( CH_3OH \) (methanol). Step 3: Correct Answer Thus, the correct answer is (CH\(_3\))\(_3\)Cl, CH\(_3\)OH.
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