The number of total electrons in an ion depends on its atomic number and the charge:
- \( \text{Na}^+ \) has 10 electrons (since Na has atomic number 11 and loses 1 electron).
- \( \text{Al}^{3+} \) has 10 electrons (since Al has atomic number 13 and loses 3 electrons).
So, \( \text{Na}^+ \) and \( \text{Al}^{3+} \) both have 10 electrons, which makes this pair correct. Let's check the other pairs:
- \( \text{O}^{2-} \) has 10 electrons (O has atomic number 8 and gains 2 electrons), and \( \text{F}^- \) has 10 electrons (F has atomic number 9 and gains 1 electron). Thus, this pair has the same number of electrons.
- \( \text{Mg}^{2+} \) has 10 electrons (Mg has atomic number 12 and loses 2 electrons), and Ar has 18 electrons. Therefore, this pair does not have the same number of electrons.
- \( \text{P}^{3-} \) has 18 electrons (P has atomic number 15 and gains 3 electrons), and Ar has 18 electrons. This pair has the same number of electrons.
Hence, the correct answer is \( \text{Mg}^{2+} \) and Ar.