Question:
When the same amount of Al is treated with an excess of $ HCl $ and $ NaOH $ , the volumes of hydrogen evolved are in the ratio of:
When the same amount of Al is treated with an excess of $ HCl $ and $ NaOH $ , the volumes of hydrogen evolved are in the ratio of:
Updated On: Jun 7, 2022
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The Correct Option is A
Solution and Explanation
Aluminium reacts with $ HCl $ and NaOH, as follows: $ 2Al+6HCl\xrightarrow{{}}2AlC{{l}_{3}}+3{{H}_{2}}\uparrow $ $ 2Al+2NaOH+2{{H}_{2}}O\xrightarrow{{}}2NaAl{{O}_{2}}+3{{H}_{2}}\uparrow $ Hence, ratio of hydrogen evolved in both cases is 1 : 1.
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Concepts Used:
Group 13 Elements
Group 13 is commonly known as the Boron Family. The boron family comprises:
- Boron (B)
- Aluminum (Al)
- Gallium (Ga)
- Indium (In)
- Thallium (Tl)
Element 113 (Nihonium) gets the name of ununtrium Uut. Each one of the elements has three electrons in the external shell of their nuclear structure is one of the important and mutual properties of the group.
The general electronic configuration for the group 13 elements is ns2 np1.
Density of Boron Family:
Melting point and Boiling Point:
Electronegativity:
Atomic and Ionic Radii:
Compounds of Group 13 Elements:
- Oxides
- Halides
- Borates
- Boron Hydrides
- Diborane
- Borazine