Question:

When propanoic acid is treated with bromine and red phosphorus in aqueous medium, 2-bromopropanoic acid is formed. This reaction is known as

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The Hell-Volhard-Zelinsky reaction is useful for introducing bromine at the alpha position of carboxylic acids, often used in synthesis of more complex molecules.
Updated On: Mar 5, 2025
  • Kolbe reaction
  • Wurtz reaction
  • Hell-Volhard-Zelinsky reaction
  • Etard reaction
  • Wurtz-Fittig reaction 
     

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The Correct Option is C

Solution and Explanation

Step 1: The Hell-Volhard-Zelinsky reaction specifically involves the halogenation of the alpha-carbon of carboxylic acids. 
Step 2: This reaction uses a halogen (Br\(_2\)) and red phosphorus, which generates phosphorus tribromide (PBr\(_3\)), acting as a catalyst. 
Step 3: Phosphorus tribromide converts the carboxylic acid to an acyl bromide, which subsequently undergoes alpha-bromination. 
Step 4: The product, 2-bromopropanoic acid, confirms the pathway and mechanism of the Hell-Volhard-Zelinsky reaction. 

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