Question:
When forces $F_1,F_2,F_3$ are acting on a particle of mass m such that $F_2$ and $ F_3 $ are mutually perpendicular, then the particle remains stationary, If the force $F_1$ is now removed Then acceleration of the particle is.
When forces $F_1,F_2,F_3$ are acting on a particle of mass m such that $F_2$ and $ F_3 $ are mutually perpendicular, then the particle remains stationary, If the force $F_1$ is now removed Then acceleration of the particle is.
Updated On: Jul 7, 2022
- $F_1/m$
- $F_1F_3 / m\,F_1$
- $(F_2-F_3)/m$
- $F_2/m$
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The Correct Option is A
Solution and Explanation
Answer (a) $F_1/m$
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Notes on Motion in a plane
Concepts Used:
Motion in a Plane
It is a vector quantity. A vector quantity is a quantity having both magnitude and direction. Speed is a scalar quantity and it is a quantity having a magnitude only. Motion in a plane is also known as motion in two dimensions.
Equations of Plane Motion
The equations of motion in a straight line are:
v=u+at
s=ut+½ at2
v2-u2=2as
Where,
- v = final velocity of the particle
- u = initial velocity of the particle
- s = displacement of the particle
- a = acceleration of the particle
- t = the time interval in which the particle is in consideration