Question:

When $Cu ^{2+}$ ion is treated with $KI$, a white precipitate, $X$ appears in solution The solution is titrated with sodium thiosulphate, the compound $Y$ is formed $X$ and $Y$ respectively are

Updated On: Sep 30, 2024

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The Correct Option is C

C u^{2 +} + 2 K I ⟶ Unstable C u I_{2} ↓ + 2 K^{+}

I^{-}

is strong R.A it reduces

C u^{2 +}

C u^{+}

2 C u I_{2} ⟶ (White)’X’ C u_{2} I_{2} ↓ + I_{2}

K I + I_{2} ⟶ K^{+} I_{3}^{-} (Brown solution)

I_{3}^{-} ⇌ I_{2} + I^{-}

K I_{3} + N a_{2} S_{2} O_{3} \to K I + (Y) N a_{2} S_{4} O_{6}

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