When chlorine reacts with hot and conc. NaOH, the products formed are
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- NaCl, NaClO$_3$, H$_2$O
- NaCl, NaOCl, H$_2$O
- NaCl, H$_2$O only
- NaOCl, H$_2$O
The Correct Option is A
Solution and Explanation
Chlorine reacts with hot concentrated NaOH as follows:
\[ 3Cl_2 + 6NaOH \rightarrow 5NaCl + NaClO_3 + 3H_2O \] This forms sodium chloride (NaCl), sodium chlorate (NaClO$_3$), and water.
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