Question

When an external magnetic field of strength \(1.5 \times 10^{-3}\) A/m is applied to a rock sample, the measured intensity of magnetization is \(0.5 \times 10^{-3}\) A/m. The magnetic susceptibility of this rock is ________ (Round off to two decimal places).

Hint:

To find magnetic susceptibility, divide the magnetization by the magnetic field strength.

Answer 1

Step 1: Magnetic susceptibility formula. Magnetic susceptibility (\(\chi\)) is defined as the ratio of the magnetization \(M\) to the applied magnetic field \(H\): \[ \chi = \frac{M}{H} \] where:
\(M\) is the intensity of magnetization,
\(H\) is the applied magnetic field strength.
Step 2: Given values and calculation.
Magnetization, \(M = 0.5 \times 10^{-3}\) A/m,
Magnetic field strength, \(H = 1.5 \times 10^{-3}\) A/m.
Substitute the values: \[ \chi = \frac{0.5 \times 10^{-3}}{1.5 \times 10^{-3}} = 0.33 \] Thus, the magnetic susceptibility of the rock is \(0.33\).