Step 1: In the CE configuration, the output is 180\(^\circ\) out of phase with the input, which is a characteristic feature of the common emitter configuration.
Step 2: In both CB and CC configurations, the phase shift is either zero or a fraction of a degree, not 180\(^\circ\). Hence, the only correct answer is the CE configuration. Thus, the correct answer is option (2), CE - configuration.
Sliding contact of a potentiometer is in the middle of the potentiometer wire having resistance \( R_p = 1 \, \Omega \) as shown in the figure. An external resistance of \( R_e = 2 \, \Omega \) is connected via the sliding contact.
The current \( i \) is : 


If the roots of $\sqrt{\frac{1 - y}{y}} + \sqrt{\frac{y}{1 - y}} = \frac{5}{2}$ are $\alpha$ and $\beta$ ($\beta > \alpha$) and the equation $(\alpha + \beta)x^4 - 25\alpha \beta x^2 + (\gamma + \beta - \alpha) = 0$ has real roots, then a possible value of $y$ is: