Question:

When a die is thrown once, the probability of getting an even number will be:

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For a fair die, the probability of getting any number = $\dfrac{1}{6}$. Count how many outcomes meet the condition.
Updated On: Nov 6, 2025
  • $\dfrac{1}{4}$
  • $\dfrac{1}{3}$
  • $\dfrac{1}{2}$
  • $\dfrac{1}{6}$
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The Correct Option is C

Solution and Explanation

Step 1: Identify total outcomes.
For a single die, total outcomes = 6 (1, 2, 3, 4, 5, 6).

Step 2: Identify favorable outcomes.
Even numbers = 2, 4, 6 → total favorable outcomes = 3.

Step 3: Apply formula.
\[ P(E) = \dfrac{\text{Favorable outcomes}}{\text{Total outcomes}} = \dfrac{3}{6} = \dfrac{1}{2} \]
Step 4: Conclusion.
Thus, the probability of getting an even number is $\dfrac{1}{2}$.
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