Step 1: Start dividing by prime numbers
$156 \div 2 = 78$ (So one factor of 2)
$78 \div 2 = 39$ (Another factor of 2)
Step 2: Continue prime division
$39 \div 3 = 13$ (Factor of 3)
$13$ is already a prime number.
Step 3: Collect prime factors
Thus,
\[
156 = 2 \times 2 \times 3 \times 13 = 2^2 \times 3 \times 13
\]
Step 4: Conclusion
Therefore, the prime factorisation of $156$ is $2^2 \times 3 \times 13$.
The correct answer is option (A).
Find the unknown frequency if 24 is the median of the following frequency distribution:
\[\begin{array}{|c|c|c|c|c|c|} \hline \text{Class-interval} & 0-10 & 10-20 & 20-30 & 30-40 & 40-50 \\ \hline \text{Frequency} & 5 & 25 & 25 & \text{$p$} & 7 \\ \hline \end{array}\]
Two concentric circles are of radii $8\ \text{cm}$ and $5\ \text{cm}$. Find the length of the chord of the larger circle which touches (is tangent to) the smaller circle.